
11 | abba, where a and b are the digits in a 4 digit number.
Nov 21, 2013 · Truly lost here, I know abba could look anything like 1221 or even 9999. However how do I prove 11 divides all of the possiblities?
matrices - When will $AB=BA$? - Mathematics Stack Exchange
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How to prove $\\operatorname{Tr}(AB) = \\operatorname{Tr}(BA)$?
Jan 11, 2015 · there is a similar thread here Coordinate-free proof of $\operatorname {Tr} (AB)=\operatorname {Tr} (BA)$?, but I'm only looking for a simple linear algebra proof.
Matrices - Conditions for $AB+BA=0$ - Mathematics Stack Exchange
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elementary number theory - Common factors for all palindromes ...
For example a palindrome of length $4$ is always divisible by $11$ because palindromes of length $4$ are in the form of: $$\\overline{abba}$$ so it is equal to $$1001a+110b$$ and …
$A^2=AB+BA$. Prove that $\det (AB-BA)=0$ [duplicate]
Let $A,B$ be two $3\times 3$ matrices with complex entries, such that $A^2=AB+BA$. Prove that $\det (AB-BA)=0$
For symmetric $A$ and $B$, show that $AB$ is symmetric if …
Oct 14, 2018 · I could easily prove this using 2x2 matrices and multiplying them together, but how do you generally prove this and using letters not matrices? (this isn't homework, we haven't …
How to calculate total combinations for AABB and ABBB sets?
Apr 19, 2022 · Although both belong to a much broad combination of N=2 and n=4 (AAAA, ABBA, BBBB...), where order matters and repetition is allowed, both can be rearranged in different …
How many $4$-digit palindromes are divisible by $3$?
Feb 28, 2018 · How many $4$-digit palindromes are divisible by $3$? I'm trying to figure this one out. I know that if a number is divisible by $3$, then the sum of its digits is divisible by $3$. All I …
algebra precalculus - If both $a,b>0$, then $a^ab^b \ge a^bb^a ...
Dec 11, 2014 · Prove that $a^a \\ b^b \\ge a^b \\ b^a$, if both $a$ and $b$ are positive.